Solving Enoch chapter 74

Enoch 74:10-12

Thus, I saw their positions how the moons rose and the sun set in those days. And if 5 years were added together the sun has an overplus of thirty days and all the days which accrue to it for one of these 5 years, when they are full amount to 364 days. And the overplus of the sun and the stars amounts to 6 days: in 5 years 6 days every year come to 30 days: and the moon falls behind the sun and stars to the number of 30 days.

Enoch 74:13 & 14 for the sun in 3 years there are 1,092 days

5 years 1,820 days

8 years 2,912 days

Enoch 74: 15 & 16

for the moon in 3 years there are 1,062 and 30 days behind the sun and stars

5 years 1,770 = 50 days behind

8 years 2,832 = 80 days behind

Now let's look at how the math works to understand why verses 11 & 12 is telling us the moon falls behind 30 days in 5 years compared to verses 13-14 that says the moon is behind the sun and stars 50 days in 5 years.

The moon has 354 days a year.

The sun has 360 + 4 seasonal or intercalary days a year.

Enoch 75:1 Explains you will go wrong if these intercalary days aren't counted in the year. So, we will use the 360-day year and then add in the 4 intercalary days separate to get a clear understanding of Enoch 74.

6 days in 5 years = 6 x 5 = 30 days

The moon is behind the 360-day solar year by 30 days in 5 years

5 x 354 = 1770 for the moon

5 x 360 = 1800 for the sun

1800 - 1770 = 30 days

6 days a year for 5 years the moon is behind the sun and stars 30 days

Now we add the 4 intercalary days that the sun and stars have extra each year.

4 x 5 =20

20 extra sun days + 30 days the moon is already behind =50 days the moon is behind the sun and stars in 5 years of the solar year of 364 days a year when they are full.

In other words, it's full when you add the 4 intercalary days and don't go wrong by not adding them as Enoch 75:1 explains.

354 x 5 years = 1770 + 50 days behind the sun = 1,820 days

364 x 5 years = 1,820 days

That is the 30 days for the moon + the 20 extra days for the sun totaling 50 days in 5 years.

We can see the same math for the 3 years, and the 8 years listed in Enoch 74: 13 -16.

3 years x 354 = 1,062 for the moon

3 years x 360 = 1,080 for the sun

1,080 - 1,062 = 18 days the moon is behind the sun at 6 days a year for 3 years.

4 intercalary days of the sun x 3 years = 12 days extra for the sun

18 + 12 = 30 days the moon is behind the sun in 3 years

8 years x 354 = 2,832 for the moon

8 years x 360 = 2,880 for the sun

2,880 - 2,832 = 48 days the moon is behind the sun at 6 days a year for 8 years.

4 intercalary days of the sun x 8 years = 32 days extra for the sun

48 + 32 = 80 days the moon is behind the sun and stars in 8 years